A bag of athletics supplies contains 12 baseballs and 8 footballs. One ball is chosen at random and replace two times. What is the probability of choosing a football both time?
A 1/10
B 14/95
C 4/25
D 2/5
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Answer:
Initially, total number of balls =12
No. of black balls =x
So, P(black ball) =
12
x
If 6 more black balls are added, total number of balls =12+6=18
NO. of black balls =x+6
P(black ball) =
18
x+6
Given the probability of drawing a black ball is now double of what it was before
So,
12
2x
=
18
(x+6)
6
x
=
18
(x+6)
3x=x+6
2x=6
x=3
So, the number of black balls present initially =3.
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