Question

A bag of flour has a weight of 12 1/2 kg. Two fifth of it was lost through a hole in the side. How much of it was left in the bag? Please tell the method to find the answer

Answer 1

Answer:

Refers to the attachment.... Left weight is 7 isto1/2 Kg

Answer 2

Answer:

initial weight=12$\frac{1}{2}$ kg

lost weight=$\frac{2}{5}$ kg

amount left in bag= 12$\frac{1}{2}$ kg - $\frac{2}{5}$ kg =(12*2+1)/2 - 2/5 = 25/2 - 2/5

                                                                                  = (125 - 4)/10

                                                                                  = 121/10 = 12.1 kg

                                                                                                      is left