A bag of fruits was distributed among 4 students P, Q, R and S. P took 3/8th of the
fruits, Q took 1/5 th of the remaining fruits and the remaining fruits were equally
distributed among R and S What fraction of fruits did R get ?
Answers
Step-by-step explanation:
Given:-
A bag of fruits was distributed among 4 students P, Q, R and S. P took 3/8th of the fruits, Q took 1/5 th of the remaining fruits and the remaining fruits were equallydistributed among R and S .
To find:-
What fraction of fruits did R get ?
Solution:-
Let the total fruits distributed among P,Q,R and S in a bag be X
Number of fruits got by P = 3/8 th of the fruits
=>(3/8)×X
=>3X/8
Number of fruits got by P = 3X/8
Remaining fruits = X-(3X/8)
=>(8X-3X)/8
=>5X/8
Remaining fruits in the bag = 5X/8
Number of fruits got by Q = 1/5th of the remaining
=>(1/5)×(5X/8)
=>(5X)/(5×8)
=>5X/40
=>X/8
Number of fruits got by Q = X/8
Remaining fruits = (5X/8)-(X/8)
=>(5X-X)/8
=>4X/8
=>X/2
Remaining fruits after they were distributed to P and Q = X/2
Remaining fruits are distributed to R and S equally then
Number of fruits got by R = (X/2)/2
=>(X/(2×2)
=>X/4
R and S got X/4 fruits each.
Answer:-
The fraction of fruits R got = X/4
Check:-
Total fruits =
Fruits got by (P+Q+R+S)
=>(3X/8)+(X/8)+(X/4)+(X/4)
=>[(3X+X)/8] +[(X+X)/4]
=>(4X/8)+(2X/4)
=>(X/2)+(X/2)
=>(X+X)/2
=>2X/2
=>X
Total number of fruits
Verified