A bag of sand of mass m suspended by a rope a bullet of mass m/40 is fired at with in a speed of v and gets emailed into it then find velocity of the bad
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there is not any information provided about the bad in the question
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Answer:
Explanation:
Given that
Mass of sand bag = M
Mass of bullet = m
Initial velocity of bullet before striking the bag = v
Lets the final velocity of bullet and bag is u because they will move together.
We know that there is not any external force so the linear momentum will be conserve.
m v =(M+m)u
So u=m v/(m+M)
Initial kinetic energy of system
Final kinetic energy of system
So the loss in kinetic energy
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