Question

A bag of sand was dropped from the top of a building of height 20 m. The velocity with which the bag reaches the ground is ?

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Answer 1

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Total height =100m=S1+S2

Using equation of motion,

For first ball

S1=ut+21gt2

where,

S= Distance

u= Initial velocity

g= acceleration due to gravity

t= time

S1=0−21gt2

For second ball

S2=40t+21gt2

S2=40t−S1__________(i)

Putting the value of S1 in equation (i)

S2+S1=40t

100=40t

t=2.5sec

Hence, two balls will meet after 2.5sec

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