Question

A bag of wheat 200 kg. To what height should it be raised so that the potential energy may be 9800 joules???​

Answer 1

Answer:

Potential energy =m×g×h (here m=200kg, g=9.8ms^−2 , potential energy =9800 joule)

9800J=200Kg×9.8ms^−2 ×h

h=9800/ 200×9.8

h=5m

Thus, the bag of wheat should be raised to a height of 5m.

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Answer 2

➽ Question :-

A bag of wheat 200 kg. To what height should it be raised so that the potential energy may be 9800 joules???

➽ Answer:

• the bag of wheat should be raised to a height of 5 metres .

➽ Given :-

• Mass of the bag = 200 kg  
• Potential energy = 9800 J  
• Gravity = 9.8 m/s²

➽ To Find :-

• Height = ?

➽ Solution :-

As we know that

• P.E = mgh

where,

• P = Potential energy
• m = Mass
• g = gravity
• h = Height

Now, putting the values in the above formula we get,

➞ 9800 = 200 x 9.8 x h

➞ h = 9800 / 200 x 9.8

➞ h = 5 m

Hence, the bag of wheat should be raised to a height of 5 metres .

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