Question

a bag of wheat bate 75 kg calculate the height to which it should be raised so that its potential energy is 7350 joule (start given g is equal to 9.8 metre per second square answer 10 metre​

Answer 1

$\huge\underline\bold\red{Answer:-}$

Given :—

Mass (m) - 75kg

Potential Energy (P.E) = 7350 J .

Gravitation (g) = 9.8m/s${}^{2}$.

To find :—

Height .

Formula Used :—

P.E = mgh .

Solution :—

P.E = mgh .

7350 J = 75kg × 9.8m/s${}^{2}$ × h

7350 J = 735h

$h \: = \: \frac{7350}{735} \\ \\ \: h = \: 10m$

Hence , The bag should be at the height of 10m.