Question

A bag of wheat weighs 200 kg. To what height should it be raised so that its potential energy may be 9800 joules? (g = 9.8 m s ^ -2 )​

Answer 1

potential energy = mgh

m = 200 kg, g = 9.8 , P. E. = 9800 J ,h =?

9800 = 200 ×9.8 × h

h = 5 meter

Answer 2

Given :-

• Mass (m) = 200kg
• Potential energy (P. E) = 9800joules
• Acceleration due to gravity (g) = $9.8 \: m \: s {}^{ - 2}$

To find :-

• Height of the wheat bag

How to solve :-

As we know $P. E = m \times g \times h$, where the value of P. E, m and g are given. It is asked to find the value of h. So, by putting the value of P. E, m and g in $P. E = m \times g \times h$ , we can find the value h.

Solution :-

• Mass (m) = 200kg
• Potential energy (P. E) = 9800joules
• Acceleration due to gravity (g) = 9.8 m s-2
• Height = ?

Putting these values in the formula,

$P. E = m \times g \times h$

$=> 9800 = 200 \times 9.8 \times h$

$=> h = \frac{9800}{200} \times 9.8$

$=> h = 5m$

So, the bag of wheat should be raised to 5m height.