Question

a bag of wheat weighs 300kg to what height should it be raised so that its potential energy may be 10000 joules , gravity = 9.8m/s2

Answer 1

Answer:

3.40 m

Explanation:

E.P=mgh

h=P.E/mg=》 h=10000/300×9.8= 3.4m

Answer 2

Answer:

${ \green { \underline{ \boxed{ \pmb{ \frak{height \: \:≈ \: 3.4 \: m \: }}}}}}$

Explanation:

Given

• Mass of the bag = 300 kg
• Potential Energy = 10000
• Acceleration due to Gravity = 9.8m/s² (constant value)

To Find :

• Height

Concept :

Formula Gonna to use :

${ \boxed{ \pmb{ {P.E \: = \: m \times g \times h}}}}$

Here ,

• P.E = Potential Energy
• m = Mass of bags
• g = gravity
• h = height

How to solve :

As we know P.E , mass and gravity are given . Here asked to find the value of height. So by substituting the value of P.E , mass and gravity in the above given formula , we get the value of Height .

Substitute the values :

$\large \hookrightarrow \rm \: \: \: {P.E = m ×g×h}$

$\large \hookrightarrow \rm \: \: \:10000 = 300 \times 9.8 \times h$

$\large \hookrightarrow \rm \: \: \:h \: = \frac{10000}{300 \times 9.8}$

$\large \hookrightarrow \rm \: \: \:h \: = \frac{10000}{2940}$

$\large \hookrightarrow \rm \: \: \:h \: = 3.40136....$

$\large \hookrightarrow \: { \purple{ \rm \: \: \:h \: ≈3.4 \: m}}$

${ \blue{ \underline { \boxed{ \pmb{ \mathcal{ \blue{ \therefore \: HEIGHT≈ \: 3.4 \: m \: }}}}}}}$