Question

A bag of wheat weighs 49 kg .calculate the height to which it should be raised so that its potential energy is 980 J ?(take g= 10 m/s2)

Answer 1

Potential energy : mgh
Mass : 49 kg

980 J = mgh
980 = 49 × 10 × h
h = 980/490
h = 2 m

Answer 2

Given:

Mass of the bag=49kg

Potential energy=980J

g=10m/$s^{2}$

To find:

The height to which the bag should be raised

Solution:

The height to which the bag should be raised is 2m.

We can find the height by taking the given steps-

We know that the energy is obtained by multiplying the mass of the bag, the height to which it is raised, and the gravitational acceleration acting on it.

Let the height to which the bag is raised be H.

The weight of the bag of wheat=49kg

The gravitational acceleration=10m/$s^{2}$

Potential energy, E=Mass of bag×Height to which it is raised×gravitational acceleration

On putting the values, we get

980=49×H×10

98=49H

98/49=H

H=2m

The bag of wheat is raised to the height of 2m.

Therefore, the height to which the bag should be raised is 2m.