A baker baked three types of cakes weighing 53÷3 kg altogether. If he baked 73÷9kg of fruit cake and 19÷6 of chocolate cake and the remaining sponge cake, what was the quantity of sponge cake ?
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Answered by
17
your correct answer is 115÷18
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59
Answer:
Step-by-step explanation:
Weight of the fruit cake =73/9kg
Weight of the chocolate cake=19/6kg
Let the weight of the sponge cake be xkg
Total weight of three cakes =58/3kg
Acc. to problem
73/9+19/6+x=58/3
Wlcm of denominator s=18
Multiplying each term by 18, we get
18×73/9+18×19/6+18×x=18×58/3
146+57+18x=348
18x=348-203
18x=145
X=145/8
Quantity of the sponge cake = 145/18kg
By kamaljeet sharma
Teacher. Sdm kishtwar
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