Question

A baker is making cup cakes. He divides his dough into 8 equal parts. He then cuts each one of these parts into 3 equal parts, each of which is the dough required to make one cupcake.
He then sells 4 such cup cakes in a packet. What fraction of the original dough is in one
packet of cup cakes?


With statements please...answer fast...urgent....​

Answer 1

Given :

No of equal parts in which he first divides the dough = 8

No of equal parts in which he further divides each of the 8 parts = 3

No of cup cakes he sell in a packet = 4

To Find :

Fraction of original dough which is in one packet of cup cakes = ?

Solution :

Let the total amount of dough be =a

After dividing the dough in 8 equal parts , each part = $\frac{a}{8}$

After further division of these 8 equal parts ,each part =$\frac{1}{3} \times \frac{a}{8}= \frac{a}{24}$

So, the dough required to make one cup cake = $\frac{a}{24}$

Total  dough required for 4 cup cakes = $\frac{a}{24} \times 4 = \frac{a}{6}$

Hence the total fraction of the original dough in one cup cake =$\frac{\frac{a}{6}}{a}= \frac{1}{6}$

So, the fraction of origin dough present in one packet of cup cake is =$\frac{1}{6}$