Question

A bal! is projected with a velocity 20_3 m/s at angle 60° to the horizontal. The time interval after
which the velocity vector will make an angle 30° to the horizontal is
(take g = 10m/s)
​

Answer 1

Answer:

2 sec

Explanation:

tan30∘=vy/vx

= uy-gt/ux

= (20√3 sin60∘)-10t / (20√3 cos60∘)

or 10=30-10t

t = 2 sec

Answer 2

Explanation:

A ball is projected with a velocity

at angle

to the horizontal. The time interval after which the velocity vector will make an angle

to the horizontal is A projectile is projected in the upward direction making an angle of

with horizontal direction with a velocity of

. Then the time after which its inclination with the horizontal is

is (g=10 ms^(-2)).