a balance coin is tossed three times ,then find the probability of (H,H,T)
Answers
Answered by
2
Step-by-step explanation:
sample space={(HHH)(TTT)(HTH)(THH)(HHT)(HTT)(THT)(TTH)}
n(S)=8
A={(HTH)(THH)(HHT)}
p(A)=n(A)/n(S)
=8/3
Answered by
2
Answer:
(T,T,T),(T,T,H),(T,H,H),(H,H,H),(H,H,T),(H,T,T),(T,H,T),(H,T,H)
Ans.=1/8
《or》
(H,H,T),(T,H,H),(H,T,H)
P(E)=no.of favorable outcomes/total no.of outcomes
3/8
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