Question

A. Balance the following chemical equations. (Any 5) [5]
i. Pb3O4 → PbO + O2
ii. Fe + H2O → Fe3O4 + H2
iii. Ca(NO3)2 → CaO + NO2 + O2
iv. HgO Hg + O2
v. K + HCl KCl + H2
vi. K + H2O KOH + H2

PLEASE GIVE STEP BY STEP METHOD I REALLY NEED HELP!!!!1

Answer 1

Explanation:

1. Pb304 = PbO + 02

Balanced equation:

2 Pb304 = 6 PbO + 02

Reaction type:

Decomposition

2. 3Fe + 4H2O Fe304 + 4H2

Iron + Water = Iron Oxide Black + Dihydrogen

Reaction Type: Single Displacement

(Substitution)

4. Hgo is an oxidizing agent, Hgo is a reducing agent.

Search by reactants (Hgo) and by products (Hg, O 2)

HgO>02 + Hg

H202 + HgO>H2O +02 + Hg

5. How to balance K+ HCI= KCI +H2 | Potassium + Hydrogen K+ HCI= KCI + H2. Chemical balance equations:- In this Video you can learn How to Balance the equation K+ HCL = KCL + H2 Count the number atoms of each element on both the side of arrow in the chemical equation and write in table.

6. 2k+2h2o=2koh+h2 is the balanced equation