Physics, asked by sai7791, 4 months ago

A balanced 3 phase star supply with a line voltage of 415V, 50Hz is connected to a balanced load having resistance of 10Ω and inductor of 42mH connected in series. Find (a) total power using two wattmeter method and power factor if the balanced load is connected in a star configuration, (b) total power using two wattmeter method and power factor if the balanced load is connected in a delta configuration.

Answers

Answered by albert82
0

Answer:

connected to a balanced load having resistance of 10Ω and inductor of 42mH connected in series. Find (a) total power using two wattmeter method and power factor if the balanced load is connected in a star configuration, (b) total power using two wattmeter method and power factor if the balanced load is connected in a delta c

Answered by ExoticWylde
3

Answer:

Power P=5000W,

line voltage VL = 400 V,

line current, IL = 8.6A and

power, P =√3 VLIL cos φ

Hence

power factor = cos φ = P √3 VLIL

= 5000 √3 (400) (8.6)

= 0.839

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