Question

A balanced delta connected load of 8 + j6 ohm per phase is connected to a 3 phase, 50 Hz, 230 V supply. Calculate Reactive and total power.​

Answer 1

Answer:

Zph = √(82 + 62) = 10Ω Vph = 400/√3 = 231V Iph = Vph/Zph = 231/10 = 23.1A (i) IL = Iph = 23.1A (ii) p.f. = cosφ = Rph/Zph = 8/10 = 0.8(lag) (iii) Power P= √3VLILcosφ = √3 x 400 x 23.1 x 0.8 = 12,800W [Also, P = 3I2phRph = 3(23.1)2 x 8 = 12,800W] (iv) Total volt-amperes, S = √3VLIL = √3 x 100 x 23.1 = 16,000VA

Explanation: