A balanced three phase star connected load is supplied from three phase 400V 50Hz supply. The resistance of each coil is 6 Ω & reactance of 8 Ω. Find the value of phase current, line current, phase voltage, line voltage & total power consumed.
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Impedance per phase r + jXL – jXC XL = 2π x 50 x 0.15 = 47.1Ω XC = 106/32.37 = 26.54Ω cosφ = 25/32.37 Lagging, since inductive reactance is dominating. Phase Current = 400/(25 + j20.56) = 12.357 Line Current = √3 x 12.357 = 21.4amp Since the power factor is 0.772 lagging, P = total three phase power = √3VLIL cosφ x 10-3KW = √3 x 400 x 21.4 x 0.772 x 10-3 = 11.446KW S = total 3 ph KVA 11.446/0.772 = 14.83KVA Q = total 3 ph “reactive kilo-volt-amp” √3 = (S2 - P2)0.50 = 9.43 kVAR laggingRead more on Sarthaks.com - https://www.sarthaks.com/494318/three-pahse-supply-feeding-three-phase-delta-connected-with-each-phase-having-resistance
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