Physics, asked by adulrakha, 9 months ago

A ball 'A' has twice the diameter as another ball 'B' of the same material and with same surface finish. 'A' and 'B' are both heated to the same temperature and allowed to cool by radiation : then;
Options:
1. rate of cooling of 'A' is same as that of 'B'
2. rate of cooling of 'A' is twice that of 'B'
3. rate of cooling of 'A' is half that of 'B'
4. rate of cooling of 'A' is four times that of 'B'

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Answers

Answered by sawakkincsem
1

The correct option is 4) rate of cooling of 'A' is four times that of 'B'.

Explanation:

  • This can be found out using Stefan's Law of cooling.

  • The formula of this law is Rate of cooling = σeAT  

  • Temperature greatly affects any surface, material or things.

  • Newton also has a derivation of the law of cooling.

  • But, both these laws differ from one another.
Answered by Princessofdarknzz
5

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