Question

a ball A is projected from the ground such that is horizontal range is maximum.another ball B is dropped from height equal to the maximum range of A.the ratio of the time of flight of A to the time of fall of B is
a)sq root 2:1
b)1:2
c)1:1
d)1:sq root2

Answer 1

Answer:

1:1

Explanation:

Ball A has some initial velocity say 'u'

when A reached its maximum height say 'h' then the velocity of the ball at height h will be zero (0).

when the ball b is dropped from the same height h then the initial velocity is zero by the time balk B reaches ground its velocity will be equal to the initial velocity of ball A i.e. 'u' m/s

if the velocities are equal then the displacement and the time taken will also be equal

Therefore the ratio of time of flight will be 1: 1.