Question

A ball a is thrown upwards. It returns 6 seconds later. What is the greatest height reached by the ball is (g=10 m/s²)

Answer 1

T=6s

a= -10M/S

V= 0

S=?

v=u+at

0=-10*6=-60

now,

2as=v^2-u^2

2*(-10)=0^2-(-60)^2

-20s= -3600

s=180m

I hope it will helpful for u.