Physics, asked by sonuagrl9717, 10 months ago

A ball A of mass 3 m is placed at a distance d from the wall on a smooth horizontal surface Another ball B of mass m moving with velocity u collides with ball A. The coefficient of restitution between the balls and the wall and between the balls is e
(a) the velocity of ball B after collision is (u(3e-1))/(4).
(b) the velocity of ball B after collision is (u(2e-1))/(4).
( c) after collision, ball A will have away by distance (d(2e-1))/((2e-1)) during the time ball B returns back to wall.
(d) after collision, ball A will move away by distance (d(e-1))/((3e-1)) during the time ball B returns back to wall.

Answers

Answered by mohammedkhajaraziudd
0

Answer:

this way is right

Explanation:

The coefficient of restitution between the balls and the wall and between the balls is e

(a) the velocity of ball B after collision is (u(3e-1))/(4).

(b) the velocity of ball B after collision is (u(2e-1))/(4).

( c) after collision, ball A will have away by distance (d(2e-1))/((2e-1)) during the time ball B returns back to wall.

(d) after collision, ball A will move away by distance (d(e-1))/((3e-1)) during the time ball B returns back to wall.

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