A ball after falling from height of 4.9m strikes a horizontal plane . If coefficient of restitution is 3/4 the ball will strike second time with the plane after how much time???
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Hey sona
Correct Answer: C
Solution :
Time taken by the ball to reach the plane t=2hg−−−√ =2×4.99.8−−−−−−√=1s Height attained by the ball after 1st bounce h=e2h =(34)2×4.9 12gt2=916×4.9 t=2×9×4.916×g−−−−−−−−−√ =18×4.916×9.8−−−−−−−√=34s So, the ball will strike second time after =2×34=32s
Correct Answer: C
Solution :
Time taken by the ball to reach the plane t=2hg−−−√ =2×4.99.8−−−−−−√=1s Height attained by the ball after 1st bounce h=e2h =(34)2×4.9 12gt2=916×4.9 t=2×9×4.916×g−−−−−−−−−√ =18×4.916×9.8−−−−−−−√=34s So, the ball will strike second time after =2×34=32s
arsh3719:
thanks for
answer
Answered by
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Here's the solution.. Answer is 3/2 sec.
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