A ball crosses same height at t=1sec and t=3sec .choose the correct option A.Total time of flight is4 sec. B.Total time of flight is 2sec. C.projection speed is 40m/sec D.projection speed is 20m/sec
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Answer:
It means it took 1 second to reach from A to B.
Due to symmetry it will take 0.5 second to reach from A to C.
Hence total time to reach from ground to C = 4+0.5=
2
9
sec
Maximum height =
2
1
×g×(
2
9
)
2
=101.25m
Length covered from C to B =0+
2
1
×g×(
2
1
)
2
=1.25m
∴ h = Maximum height - CB
=101.25−1.25=100m
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