Question

A ball doesn't bounce as high during the second bounce as they do in the first. Explain.

Answer 1

Answer:

The force of the floor pushing against the ball throws the ball back up into the air. The reason it doesn't bounce higher than where it started is simple: some of the ball's energy is lost as heat when it bounces, so it doesn't have as much going up as it did coming down.

Explanation:

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Answer 2

A ball doesn't bounce as high during the second bounce as they do in the first.

• It's obvious why it doesn't rebound higher than it was when it first started as the ball bounces, part of its heat is a form of energy loss., so it doesn't have as much energy going up as it had coming down.

• Let's look at the energy of the ball assuming an indefinitely hard and flat surface.

• The initial potential energy of a ball dropped from a height of h is mgh. You'd expect it to accelerate to a certain speed.

       v=√2gh.

• During the descent, however, it will be subjected to air drag.

• Some of the ball's energy will be dissipated into air energy as a result of this (turbulence, heating, flow). The size of this effect is determined by the ball, its height, and other factors.  

• During impact, the ball's centre of mass strives to keep travelling, while the surface it touches tries to stop it.

• The ball's potential energy was turned into elastic energy. You may envision the ball's mass is coupled to a spring that compresses when you contact the floor, but friction (both inside the ball and between the ball and the floor) wastes energy.