Question

a ball dropped from a building takes 4 second to reach the ground. calculate the height of the building. ( take g=10 m/s )​

Answer 1

Answer:

$Time =\frac{\sqrt{2h} }{\sqrt{g} }$

4 s = √2h / √10

4 s = √h/√5

√h = 4√5 m

h = 80 m

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Answer 2

Explanation:

Let s=distance or height in metres

u=initial velocity in metres per seconds

g=acceleration due to gravity in metres per seconds per second

t=time in seconds

s = ut + 0.5gt^2

= 0(10) + 0.5(9.8)(10)^2

= 0 + 4.9(100)

490m

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