Question

a ball dropped from a certain height and it touches the surface of the water after 10 sec then calculate the height above which the ball was dropped​

Answer 1

Answer:

t= 10 sec

acceleration due to gravity is 9.8m/s²

9.8=v-u/10

= 98=v-u

u=0 as the ball is droped

98m/s=v

s=0x10+1/2 X 9.8 X 10 X 10

=1/2X 980

=490 m