A ball dropped from a height 100 m covers distance 5 m in Is. The distance covered in
second will be..........
(a) 80 m
(b) 700 m
(c) 750 m
(d) 800 m
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Let the ball dropped down is a and the ball thrown up is b. also the stone thrown upwards cover a distance of x and the other covers a distance of (100 –x).
For ball a
u=0
g=10m/s
2
d=(100−x)
Using the equation
s=ut+
2
1
at
2
100−x=5t
2
.........(1)
For ball b
d=x
g=−10m/s
2
u=25m/s
s=ut+
2
1
at
2
x=25t−5t
2
............(2)
Solving equation (1) and (2)
100=25t
t=4seconds
Put the value of t in equation (1)
x=100−80
x=20m
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