Physics, asked by nermin, 7 months ago

A ball dropped from a height. Find (a) Acceleration (b) Distance after 3 seconds (c) Time in air if final velocity is 20 m/s. Acceleration due to gravity = 10 metre per second square.

Answers

Answered by girishsatyawali146
5

Answer:

Distance (s) =20 m

Initial velocity =0 m/s

g=10 m/s

2

By using the formula:

v

2

=u

2

+2as

v

2

=0

2

+2×10×20

v

2

=400

v

2

=

400

v=20m/s

For calculating time:

V=u+at

20=0+10×t

t=

10

20

t=2 sec

The the stone will hit the ground with a velocity of 20 m/s in sec.

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