A ball dropped from a height "h" reaches the ground in time T. What is the height of the ball at the time
(T/2)?
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The answer is h/t....
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As the ball is dropped, the distance travelled by it is given by : s = 0.5 × g × t^2 . so at T/2 distance travelled is h/4. thus height of ball is 0.75h. Originally Answered: A ball dropped from a height "h" reaches the ground in time T.
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