Question

A ball dropped from a height h1 = 1600 mm is
observed to rebound to a height h2 = 1100 mm
from a horizontal floor. Determine the coefficient
of restitution.​

Answer 1

Explanation:

A ball dropped from a height h1 = 1600 mm is

observed to rebound to a height h2 = 1100 mm

from a horizontal floor. Determine the coefficient

of restitution.

Answer 2

Answer:

The Coefficient of Restitution (e) between the ball and ground is 0.829.

Explanation:

Coefficient of restitution (e) is referred as the ratio of velocity of separation of 2 bodies to velocity of approach of the 2 bodies.

$e=\frac{velocity\ of\ separation}{velocity\ of\ approach}$

Given in the question is a ball which is released from a height of 1.6m and after bouncing from the ground it bounces to 1.1m height.

Velocity of the ball just before colliding the ground ,

$v=\sqrt{2gh} =\sqrt{2\times 10\times 1.6}=\sqrt{32}\ m/s$

Velocity of the ball just after striking the ground

$v=\sqrt{2gh} =\sqrt{2\times 10\times 1.1}=\sqrt{22}\ m/s$

$e=\frac{velocity\ of\ separation}{velocity\ of\ approach}=\frac{\sqrt{22} }{\sqrt{32} } =0.829$

Hence,Coefficient of Restitution between the ball and ground is 0.829.