Question

A ball dropped from a height of 2m rebounds to a height of 1.5m after hitting the ground.Then the % of energy lost

Answer 1

Answer:

25℅ is the answer......................

Answer 2

Answer:

25 %

Step-by-step explanation:

Given:

Initial height of the ball, $h_{i}=2\textrm{ m}$

Final height of the ball, $h_{f}=1.5\textrm{ m}$

Energy lost by the ball is equivalent to the percentage decrease in the height of the ball.

So, decrease in height of the ball is, $\Delta h=h_{2}-h_{1}=2-1.5=0.5\textrm{ m}$

Now, percentage decrease in height is given as:

$\textrm{Percent decrease}=\frac{\Delta h}{h_{i}}\times 100\\\\\textrm{Percent decrease}=\frac{0.5}{2}\times 100\\\\\textrm{Percent decrease}=\frac{50}{2}=25 \%$

Therefore, the % energy lost by the ball is 25 %.