a ball dropped from a height,travels a distance 5m in last second of its motion.find time of flight of ball.
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Heya user !!
Here's the answer you are looking for
Let the height of the tower is h and time taken by it to reach the ground from height h is t.
Since, it is dropped, it's initial velocity (u) = 0
Using the second equation of motion,
The last second means at t = √(h/5)th second.
So, at t = √(h/5)th second, the ball travels 15m
Therefore, the height of the tower is 20m.
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