Question

a ball dropped from a tower A reaches the ground in 5 second another ball dropped from a tower B reaches the ground in 10 seconds.If the height of the tower is A is 122.5m what is the height of Tower b?

Answer 1

where h=height of tower, u=initial velocity=0, t = time of flight=8 s, ... so h=0+0.5*10*8^2 m=5 *64 m=320 m ... Time taken by the object to reach the ground is 8 seconds, t=8sec.

Answer 2

Given:
Initial Speed(u) = 0m/s
Time taken from tower2(t) = 10s
Acceleration due to gravity(g)= 10m/s(Approx.)
We know,
S=ut +1/2 x at²(Here a will be taken as g as the object is under the influence of gravity)
S=0x10 + 1/2 x 10 x 10²
S=1/2 x 1000
S=500m
Height of the tower is 500m.