Question

A ball dropped from height of 10m is found to rebound back to height of 9m. During its first rebounce what will be height of rebounce for third rebounce?​

Answer 1

Answer:

Ans.1) 2100m/s.

Explanation:

Let u be the velocity with which the ball hits the ground, then

u

2

=2gh

=2×9.8×10=196

∴u=14m/sec

If v be the velocity with which it rebounds, then

v

2

=2×9.8×2.5=49

⇒v=7m/sec

∴Δv=(v−u)

=(7m/sec)−(−14m/sec)

=21m/sec

∴a=

Δt

Δv

=

0.01

21

=2100m/s.

Please the the brainliest.