Question

A ball dropped from the top of a tower, falls first half of hieght in 5s. The total hieght of tower is (g=10m/s2).
(please help me asap)​

Answer 1

Answer:

250m

Explanation:

we know that s=ut+$\frac{1}{2}$at²

if the height of the tower is x....then x/2 is it's half

substituting it

s=0+$\frac{1}{2}$at²            (the ball is dropped so initial velocity u = 0m/s)

s=10x$\frac{1}{2}$x25

s=250/2

s=125m => half of the tower

total height of the tower = 2s= 250m