Question

A ball dropped from the top of tower falls first half
height of tower in 10 s. The total time spend by ball
in air is [Take g = 10 m/s]​

Answer 1

Answer:

14.14 seconds

Explanation:

Let h be the height of the tower.

Given that at t= 10 sec , distance travelled =h / 2

Using the equation , S=ut + (1/2)at2

Here u =0 , a =10 m/s2 , t= 10 sec

S = 0 + (1/2) × 10×(10)2

S = 500 m

So half the height of tower = 500 m

i.e h/ 2 = 500 m

h = 500×2 m

h=1000 m

Total time taken by the ball can be determined by using the equation, S=ut + (1/2)at2

Here S =1000 m , t = ?

1000 = (1/2)×10×t2

t2 = 2000 / 10

t = 14.14 sec