Question

A ball dropped from the top of tower falls first half height of 10s.the total time spend by ball in air is ( g=10m/s²)

Answer 1

s= ut + ½ at2

Let the height of tower be 2h.

h= 0 + ½ * g * t2

=1/2 * g * 102

=50g

2h = ½ * g * T2

100g = ½ * g * T2

200 = T2

T = 2001/2

T = 10 root 2 seconds