a ball falls freely from the rest and the total distance covered by it in the last second of its motion is equal to the distance covered by it in the first 5 seconds of its motion the total time of the stone when it is in the motion would be
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Answered by
148
Given u=0.
Distance covered in first 5 sec
= ut + 1/2 * g * t^2
= 1/2 * 10 * 5*5
=125 m.
According to question,
Distance travelled in last second = Distance travel in first 5 sec.
Snth = u + a/2* (2n - 1) =125m
10/2* (2n - 1) =125
2n - 1 = 25
2n = 26
n = 26/2
=13 sec.
Means total time = 13 sec.
Hope it's helpful to u.
Distance covered in first 5 sec
= ut + 1/2 * g * t^2
= 1/2 * 10 * 5*5
=125 m.
According to question,
Distance travelled in last second = Distance travel in first 5 sec.
Snth = u + a/2* (2n - 1) =125m
10/2* (2n - 1) =125
2n - 1 = 25
2n = 26
n = 26/2
=13 sec.
Means total time = 13 sec.
Hope it's helpful to u.
Answered by
27
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