Question

a ball falls freely under gravity. The distance covered in first ,second , third seconds of motion are in ratio​

Answer 1

Answer:

Distance travel is time t is :

s = ut + 1/2at2initial velocity u= 0s = 1/2at2distance travelled in 1 second = s1 = 1/2×9.8 ×12 = 4.9 msimilarly distnace travelled in 2,3,4 seconds ares2 = 19.6 ms3 =44.1 ms3 = 78.4 m

Now distance travelled in first(D1), second(D2) , third(D3) and fourth(D4) second are:

D1 =s1 = 4.9 mD2 = s2 − s1 = 19.6 − 4.9 = 14.7 mD3 =s3 − s2 = 44.1 − 19.6 = 24.5 mD4 = s4 − s3 = 78.4 − 44.1 = 34.3 mratio D1:D2:D3:D41:3:5:7