A ball falls from a height 10m,strikes the ground and rise back to height 8m.Find the loss of mechanical energy
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V²= 2as
v²= 2×10×10=200
velocity of approach =10√2
v² = 2×10×8= 160
v = 4√10
loss in mechanical energy = m×10(10-8)
= 20m J
v²= 2×10×10=200
velocity of approach =10√2
v² = 2×10×8= 160
v = 4√10
loss in mechanical energy = m×10(10-8)
= 20m J
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