A ball falls from a height of 100 mts. on a floor. If in each rebound, it describe (4/5)th height of the previous falling height, then the total distance travelled by the ball before it come to rest is??
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Answer:
hey there!
here's ur answer
Step-by-step explanation:
given height = 100m
for first time it will take 100m,then 2(100).4/5,....and so on till infinity
so s = 100 + 2(100).4/5 + 2(100).4/5^2 + 2(100).4/5^3....infinity
=> 100 + 2(100).4/5 [ 1 + 4/5 + 4/5^2....infiity]
=> 100 + 2(100).4/5 [ 1 divided by 1/5 ]
=> 100 + 800*5/5
=> 900 m
so distance travelled = 900 m
Hope it helps u!
Thanks
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