Question

A ball falls from height of 10 m on a ground plane where it loses 40% of its energy due to impact. Then after two impacts the ball will reach upto height

Answer 1

let the mass of the ball be "m"

h₁ = initial height before bounce for the ball = 10 m

initial potential energy before bounce is given as

PE₁ = mg h₁

h₂ = final height after bounce for the ball = ?

final potential energy after bounce is given as

PE₂ = mg h₂

Using conservation of energy

PE₂ = 60% of PE₁ (Since remaining 40% energy is lost)

mg h₂ = 0.60 mg h₁

h₂ = (0.60) (10)

h₂ = 6 m