Question

a ball falls off a table and reaches the ground at 1s assuming g=10m/s2 calculate it's speed on reaching the ground and the height of the table

Answer 1

Hope you like my process

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Formula to be used

=> H = ut + ½gt²

=> V = √(u²+2gH)

where

H = height

g = gravity (10 m/s²)

u = initial velocity

V = final velocity

t = Time taken

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Given :-

=> g = 10 m/s²

=> u = 0 m/s. [ since its free fall i.e.  without any external force]

=> t = 1 sec

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Now

=> Height of table = H = ut + ½ gt²

= 0 + ½ × 10 × 1² = 5 metre

=> Velocity ( speed) reaching the ground

= V = √(u² + 2gH) = √(0 + 2×10×5)

= √(10×10) = 10 m/s

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So. the required answers are

=> Height of table (H) = 5 m

=> Speed reaching ground (V) = 10 m/s

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Hope this is your required answer

Proud to help You.

! Happy Republic Day !

Answer 2

ANSWER :

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Formula : H = ut + ½ gt²
V = √(u²+2gH)

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Given :

» g = 10 m/s ²

» u = 0 m/s ²

» t = 1 s

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Now,

» HEIGHT OF TABLE :

» H = ut + ½ gt²

= 0 + ½ + 10 × 1² = 5 m

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» Speed reaching the ground :

= S = √(u² + 2gH) = √(0 + 2 × 10 × 5)

= √(10 × 10) = 10 m/s

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» Height of the table = 5m


» speed reaching ground = 10 m/s

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