Question

A ball falls off a table and reaches the ground in 1 s. Assuming g = 10 m/s², calculate its speed on reaching the ground and the height of the table..... ​

Answer 1

Answer:

Initial velocity u=0 Let final velocity is v and height is h.

Using v=u+at

⇒v=0−10×1=−10m/s

Using s=ut+

2

1

at

2

⇒−h=0×1−

2

1

×10×1

2

⇒h=5m

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Answer 2

Given

♠Initial velocity=0

♠acceleration due to gravity=10m/s²

♠Time=1s

To Find

• Height
• Velocity

Solution

Height= $ut + \frac{1}{2} g {t}^{2}$

$= > 0 \times t + \frac{1}{2} \times 10 {t }^{2} = 5m$

velocity ² = u²+2gs

v²=0+2×10×5

v²=100

v=10

Hope it helps you...