Question

A ball falls off a table and reaches the ground in 1 s. assuming g=10 m/s2 , calculate its speed on reaching the ground and the heights of the table

Answer 1

Here are the formula that you should use:

dv = gdt

ds = t dv = gtdt

To get the values of V and S, integrate the equations. Thus:

V = gt + C; where g is the acceleration of gravity which as you said shouh be taken as 10m’sec^2, t is the time duration equal to 1 second and V = the velocity as the ball hits the ground. When t = 0, V = 0 hence the constant of integration C is 0. Thus the equation for finding V is;

V = gt.

S = (1/2)gt^2 + C; where S is the height of the fall which is the height of the table when t = 1 sec and C is the constant of integration. When t is 0, S is 0 hence C is 0 thus

S = (1/2)gt^2

Answer 2

u=0m/s
h=?
g=10m/s2
t=1 second
using 2nd equation
h=ut+1/2(gt^2)
h=0+1/2*(10*1^2)
h=1/2*(10)
h=5m