A ball falls off a table and reaches the ground in 1 s.
Assuming g = 10 m/s², calculate its speed on reaching the
ground and height of the table
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Answer:
1) velocity on reaching the ground
v=u+gt
v - final velocity
u - initial velocity
t- time
g- gravitational acceleration
Doing the substitution we have :
v= 0+10×1=10m/s
=10m/s
2) the height of the table
s=ut+1/2gt2
Doing the substitution we have:
s= 0×1+1/2×10×1
s=0+5
=5 meters
so, 5 meters is the answer
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