Question

A ball falls off the table and reaches the ground in 1 second. Assuming g=10m/s square, find out the height of the table

Answer 1

since acceleration is constant so we can use equation of motion-

let height of table be 'h'

so,
$h = ut + \frac{1}{2} g {t}^{2} \\ = 0 + \frac{1}{2} \times 10 \times {1}^{2} \\ = 5$

★★height will be 5 metres★★

Answer 2

Heya...

Here's your answer....

v = u + at

v =  gt

v = 10 ms⁻¹

h = 1/2 gt²

h = 5m

Thanks...!!!

XD

Sorry baby 'wink'