A ball falls to the ground as shown below. A* Potential energy = 120J Kinetic energy =0 B* Kinetic energy = 50J C* Potential Energy = 0 1) What is the KE of ball when it hits the ground? 2) what is PE of the ball at B? 3) Which law have you made in answering this question?
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1) By conservation of total mechanical energy:
total energy at A= total energy at C
(PE + KE) at A= (PE + KE) at C
120+0 =K.E +0
so K.E = 120J
2)...
(PE + KE) at A= (PE + KE) at B
120+0 = PE + 50
so PE = 70 J
3) We got the answer by applying law of conservation of total mechanical energy.
total energy at A= total energy at C
(PE + KE) at A= (PE + KE) at C
120+0 =K.E +0
so K.E = 120J
2)...
(PE + KE) at A= (PE + KE) at B
120+0 = PE + 50
so PE = 70 J
3) We got the answer by applying law of conservation of total mechanical energy.
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