A ball fired from land to water . at a height of 9.1 m Component liver SPEED ball direction, x is 7.6 m / s and careful Directions y is 6.1 m / s .
IF gravitational acceleration g = 9.8 m / s ² , the maximum elevation What can be achieved with more or less equal balls ....
Anonymous:
Which standard question is this?
to review for Maximum Height vy then required to use the formula ?
Which class you are in?
10?
yes :D
Chapter?
harmonic motion
Awww I've not done this chapter! In science we've only done two chapters.............sorry I can't answer I think :( !
oh ,hmm okay ,thank you ,oh please check http://brainly.in/question/504757 true or false?
Sure
Answers
Answered by
2
Initial height = h1 = 9.1 m
Horizontal component of velocity = ux = 7.6 m/s
vertical velocity component = uy = 6.1 m/s
g = 9.8 m/s^2
additional height the ball will fly = h2 = uy^2 / 2g = 1.898 m
we use s = (v^2 - u^2 ) / 2a formula.
So total height = h1 + h2 = 10.998 m = 11 m nearly
Horizontal component of velocity = ux = 7.6 m/s
vertical velocity component = uy = 6.1 m/s
g = 9.8 m/s^2
additional height the ball will fly = h2 = uy^2 / 2g = 1.898 m
we use s = (v^2 - u^2 ) / 2a formula.
So total height = h1 + h2 = 10.998 m = 11 m nearly
good ,thank yo sir! :D
Sir,if i use it :
vty²=voy²-2gh
6,1²=vo²-2.(9,8).(9,1)
37,2=vo²-178,4
voy²=215,5
voy =√215,5
------=14,68 m/s----,So
vty²=voy²-2gh
0 =voy²-2gh
2gh=voy²
h=voy²
2g
=(14,68)²
2.(9,8)
=215,5
19,6
=10,99 m
=11 m
be yes sir?
6,1²=vo²-2.(9,8).(9,1)
37,2=vo²-178,4
voy²=215,5
voy =√215,5
------=14,68 m/s----,So
vty²=voy²-2gh
0 =voy²-2gh
2gh=voy²
h=voy²
2g
=(14,68)²
2.(9,8)
=215,5
19,6
=10,99 m
=11 m
be yes sir?
Dont understand this series of calculations... U r making it complicated....
just one line answer to this question....
9.1 m + (6.1^2/2*9.8) m = 11 m
yes sir , I taught always like that , he said that I could analyze more deeply formula : D
Answered by
2
9.1 m + (6.1^2/2*9.8) m = 11 m
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